Answer:
The ratio of the secondary to primary current is:
\(\frac{I_{2}}{I_{1}} = \frac{Z_{1} E_{2}^{2}}{Z_{2} E_{1}^{2}} = \frac{4n}{(1 + n)^{2}}\)
Explanation:
This problem uses the fundamental transformer equations, which relate the voltages, currents, and impedances on the primary and secondary sides of a transformer. The key concepts involved are:
- Transformer turns ratio: \( n = \frac{c}{v} \)
- Impedance transformation: \( Z_{2} = Z_{\text{load}} \) reflected to primary
- Current ratio: Derived from the impedance and voltage ratios
The equations show how the currents relate to the voltages and impedances, considering the effects of the transformer turns ratio and the impedance of the load.
Steps:
- Start with the transformer current ratio formula:
This relates the currents to the impedances and the squared voltages.
- Express the voltages in terms of the turns ratio \( n \):
- Express the impedance ratio considering the turns ratio:
- Substitute \( E_{2} = n E_{1} \) and \( Z_{2} = Z_{1} n^{2} \) into the initial ratio:
But the problem involves specific impedance expressions, so further algebraic manipulation is needed based on the given formulas.
- Use the given impedance expressions:
and the relation:
which simplifies to:
- Express \( Z_{1} \) and \( Z_{2} \) in terms of \( n \):
and similarly for \( Z_{2} \), leading to the final ratio:
which matches the given formula.
Summary:
The problem involves the application of transformer impedance and current relationships, using the turns ratio \( n \) and the impedance transformation formulas. The key mathematical concepts are the transformer equations, impedance reflection, and voltage-current relationships in AC circuits.