Solve for x in 5x = 25: Question 8Select one: 4 1 3 2
Answer: 5 Explanation: Solve \(5x=25\) by dividing both sides by 5: \(x=\frac{25}{5}=5\). Note: none of the provided choices (4, 1, 3, 2) equals 5, so the correct value isn’t listed.
What is 35mph in Kilometers per hour? with Some other Examples
Answer: \(35\ \text{mph} = 56.32704\ \text{km/h}\) (≈ \(56.33\ \text{km/h}\)) Explanation: Use the conversion \(1\ \text{mile} = 1.609344\ \text{km}\), so multiply mph by \(1.609344\): \[ 35\times1.609344 = 56.32704. \] Some other examples (mph → km/h): \(30\ \text{mph} = 30\times1.609344 = 48.28032\ \text{km/h}\) (≈ 48.28) \(50\ \text{mph} = 80.4672\ \text{km/h}\) (≈ 80.47) \(60\ \text{mph} = 96.56064\ \text{km/h}\) […]
What is 35mph in Kilometers per hour?
Answer: 56.32704 km/h (≈ 56.33 km/h) Explanation: Use the conversion \(1\ \text{mile} = 1.609344\ \text{km}\). So \(35\ \text{mph} = 35 \times 1.609344 = 56.32704\ \text{km/h}\), which rounds to \(56.33\ \text{km/h}\).
How many kilobytes are in megabytes with Examples
Answer: There are two common answers: Decimal (SI): 1 megabyte (MB) = 1000 kilobytes (KB). Binary/IEC: 1 mebibyte (MiB) = 1024 kibibytes (KiB). (Historically many people also call this “1 MB = 1024 KB”.) Explanation: In the decimal system used by SI prefixes, 1 KB = 1000 bytes and 1 MB = 1000 × 1000 […]
What is the missing number in the table? x | 1 2 3 4 5 y | 6 36 216 ??? 7,776 A. 252 B. 396 C. 864 D. 1,296
Answer: 1,296 Explanation: Subject: Math — pattern recognition / sequences (geometric progression) and exponential functions. The y-values form a geometric sequence with common ratio 6 (36/6 = 6, 216/36 = 6, 7,776/1,296 = 6). That yields the rule y = 6^x, so for x = 4, y = 6^4 = 1,296. Steps: Compute successive ratios: […]
Question 5 Which division expression could this model represent? Each large square represents 1 whole. A. 3 ÷ 0.05 B. 0.5 ÷ 3 C. 3 ÷ 0.5 D. 3 ÷ 5
Answer: 3 ÷ 0.5 Explanation: Subject: Math (decimals and division, interpreting area/strip models). Each large square is 1 whole and is divided into 10 equal vertical strips, so each strip = 0.1. Two strips of 0.1 make 0.2, five strips make 0.5 (half a whole). The model groups the strips in halves (5 strips per […]
Question 23 of 25 Line s is the perpendicular bisector of JK. If line s intersects JK at point L, which of the following statements must be true? Check all that apply. A. Line s is perpendicular to JK B. Line s intersects JK at a 180° angle C. Line s is parallel to JK D. Point L is the midpoint of JK E. JL = KL
Answer: A, D, E Explanation: Subject: Geometry. Relevant concept: perpendicular bisector (and the Perpendicular Bisector Theorem). By definition, a perpendicular bisector of segment JK is a line that (1) is perpendicular to JK and (2) bisects JK (cuts JK into two equal parts). Therefore: A is true because “perpendicular bisector” means the line is perpendicular […]
What is an example of the transitive property of congruence?
Answer: If \( \overline{AB} \cong \overline{CD}\) and \( \overline{CD} \cong \overline{EF}\), then \( \overline{AB} \cong \overline{EF}\). Explanation: Congruence is transitive: when two figures are each congruent to a third figure, they are congruent to each other. The same holds for angles (e.g., if \(\angle A\cong\angle B\) and \(\angle B\cong\angle C\), then \(\angle A\cong\angle C\)).
What Roman numerals should be multiplied to equal 35?
Answer: V × VII = XXXV Explanation: V = \(5\) and VII = \(7\). \(5\times7=35\), and 35 in Roman numerals is XXXV.
Question 1 of 10 If JK ⟂ LM, which statement is true? A. JK and LM meet at a straight angle. B. JK and LM are coplanar and do not intersect. C. JK and LM meet at a right angle. D. JK and LM are not in the same plane.
Answer: C. JK and LM meet at a right angle. Explanation: Subject: Geometry — lines and angles. Key concepts: definition of perpendicular lines, right angle, intersection, coplanar. By definition, if two lines are perpendicular (JK ⟂ LM), they intersect and form right angles (90°). That directly makes option C true. Option A (straight angle = […]