Answer: 1738
Explanation:
This problem involves basic subtraction of large numbers. The key concept is straightforward arithmetic subtraction, which can be simplified by breaking down the problem into manageable parts or using the standard algorithm for subtraction.
Steps:
- Write the problem:
- Subtract the units digits:
2 – 4 = -2, which is negative, so borrow 1 from the tens place.
- Borrow from the tens digit (1 in 5712):
1 becomes 0, and the units digit (2) becomes 12.
- Now, subtract units:
12 – 4 = 8
- Move to the tens digits:
0 (after borrowing) – 8 = -8, so borrow 1 from the hundreds digit.
- Borrow from the hundreds digit (7):
7 becomes 6, and the tens digit (0) becomes 10.
- Subtract tens:
10 – 8 = 2
- Now, hundreds digits:
6 – 9 = -3, so borrow 1 from the thousands digit.
- Borrow from the thousands digit (5):
5 becomes 4, and hundreds digit (6) becomes 16.
- Subtract hundreds:
16 – 9 = 7
- Finally, thousands digits:
4 – 3 = 1
Result:
Putting all the digits together: 1 (thousands), 7 (hundreds), 2 (tens), 8 (units) gives 1738.
Therefore, the answer is 1738.