Concepts
synthetic division, polynomial division, linear divisor, coefficients
Explanation
This problem asks you to use synthetic division to divide a linear factor into a polynomial. The setup given corresponds to dividing a degree 1 polynomial by (x−2). The coefficients 7 and −18 stand for 7x−18.
Step-By-Step Solution
Step 1
Set up the synthetic division. The number on the left (2) is the value to use for the synthetic division, representing x=2
Coefficients: 7 (for x), −18 (constant)
Carry down the first coefficient:
| 2 | 7 -18
Carry down 7:
| 2 | 7 -18 | | 14 | 7 -4
Step 2
Multiply the carried down 7 by 2:
7×2=14
Write 14 under −18
Step 3
Add −18+14=−4
So the bottom row of synthetic division is 7 and −4
Step 4
Interpret the result:
- The quotient corresponds to 7 (constant, since original polynomial was 7x−18, a degree 1 polynomial)
- −4 is the remainder.
So, x−27x−18=7, remainder −4
Or, in polynomial form: 7x−18=(x−2)⋅7+(−4)
Quotient in polynomial form: 7 with a remainder of −4
Final Answer
Quotient: 7 Remainder: −4
In polynomial form:
7
with remainder −4