The correct answer is: 120
Explanation
This is a permutation problem because the medals are different (first, second, third), so the order in which runners are chosen matters.
Steps:
- Use the permutation formula: $$P(n,k)=\frac{n!}{(n-k)!}$$
- Substitute $n=6$ and $k=3$: $$P(6,3)=\frac{6!}{(6-3)!}=\frac{6!}{3!}$$
- Compute: $$\frac{6!}{3!}=\frac{720}{6}=120$$
Therefore, there are 120 ways to award the three distinct medals. (Equivalently: $6\times5\times4=120$.)