• Home /
  • solutions /
  • Biology /
  • At a competition with 6 runners, medals are awarded for first, second, and third places. Each of the 3 medals is different. How many ways are there to award the medals? Decide if this is a permutation or a combination, and find the number of ways to award the medals.

Question

At a competition with 6 runners, medals are awarded for first, second, and third places. Each of the 3 medals is different. How many ways are there to award the medals? Decide if this is a permutation or a combination, and find the number of ways to award the medals.

NewBlackStudio Ai Solution

100% (3 rated)

Answer

The correct answer is: 120

Explanation

This is a permutation problem because the medals are different (first, second, third), so the order in which runners are chosen matters.

Steps:

  1. Use the permutation formula: $$P(n,k)=\frac{n!}{(n-k)!}$$
  2. Substitute $n=6$ and $k=3$: $$P(6,3)=\frac{6!}{(6-3)!}=\frac{6!}{3!}$$
  3. Compute: $$\frac{6!}{3!}=\frac{720}{6}=120$$

Therefore, there are 120 ways to award the three distinct medals. (Equivalently: $6\times5\times4=120$.)